## Pages

Welcome to William's Math Analysis Blog

## Wednesday, November 13, 2013

### SV Unit J: Concept 3-4: Martrices

Though this unit we learn how to solve a matrix. With the matrix we are able to find points and to understand how a matrix works. The first thing that we have to do is choose the order that we want the equations to be in, with this we can start canceling numbers to the point where its easier to find the points. We have to find the first zero at the bottom of the matrix. we do the same thing for the second row and later with the second space on the bottom row. Later we have to be able to create a stairway of ones which we can later use to plug in numbers to find the values of the function. Then you just have to find the triple ordered pair.

## Friday, November 8, 2013

### SV#3 Unit H: Concept 7 Finding Log using approximations

In this video i work show how to find logs by using given aproximations. The first thing that we have to do is look at the clues that are given and then use them in order to divide the logs and make them into a simpler version. we also have to remember that there are some clues for the logs that are not given to us but we know them because of the property of the logs. Then after we divide the log into the most simple version we can replace the logs with the letter which they equal to, and then you just write it down.

## Monday, November 4, 2013

### WWP#6 Unit I: Concept 3: The Basics of Banking Accounts

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### SP # 3 Unit I Concept 1: Graphing Exponential Functions

In this picture I solve a problem where i demonstrate how to graph exponential functions and how to identify the x & y intercepts, asymptotes, domain, and range. First we have to identify what the values for a, b, h and k are. With that we find the asymptote. Later we have to find the x-intercept of the graph by plugging 0 into y. Then you find the y intercept by plugging 0 into x. With those values you can choose 4 key points that will help in the graphing of the formula. The domain for these will always be negative infinity to infinity. The range is the tricky part for this kind of function you have to choose the infinite that corresponds to it and then replace the other infinite by the asymptote.